\begin{equation}
\triangle L = 0,79 \times 1,475 \times 10^{-3} = 1,11 \times 10^{-3} m \nonumber
\end{equation}
\begin{equation}
\alpha = \frac{1,11 \times 10^{-3}} {0,75 \times (100 - 26)} \approx 2 \times 10^{-5} \ ºC^{-1} \nonumber
\end{equation}
\item Tin:
\begin{equation}
\triangle L = 0,58 \times 1,475 \times 10^{-3} = 8,55 \times 10^{-4} m \nonumber
\end{equation}
\begin{equation}
\alpha = \frac{8,55 \times 10^{-4}} {0,75 \times (100 - 27)} \approx 1,56 \times 10^{-5} \ ºC^{-1} \nonumber
\end{equation}
